$A$ conducting rod $AB$ of length $l = 1\,m$ is moving with a velocity $v = 4\,m/s$. The velocity vector makes an angle of $30^o$ with the length of the rod. $A$ uniform magnetic field $B = 2\,T$ exists in a direction perpendicular to the plane of motion. Then:

  • A
    $V_A - V_B = 8\,V$
  • B
    $V_A - V_B = 4\,V$
  • C
    $V_B - V_A = 8\,V$
  • D
    $V_B - V_A = 4\,V$

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