(B) The induced emf $(\varepsilon)$ across the radius of a rotating disc in a magnetic field is given by the formula: $\varepsilon = \frac{1}{2} B \om

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(B) The induced emf $(\varepsilon)$ across the radius of a rotating disc in a magnetic field is given by the formula: $\varepsilon = \frac{1}{2} B \omega R^2$.Given:Radius $R = 0.1 \, m$Frequency $f = 10 \, rev/s$Magnetic field $B = 0.1 \, T$Angular velocity $\omega = 2\pi f = 2 \times \pi \times 10 = 20\pi \, rad/s$.Substituting the values into the formula:$\varepsilon = \frac{1}{2} \times 0.1 \times (20\pi) \times (0.1)^2$$\varepsilon = \frac{1}{2} \times 0.1 \times 20\pi \times 0.01$$\varepsilon = 0.1 \times 10\pi \times 0.01$$\varepsilon = \frac{\pi}{100} \, V$.

Class 12 Physics Electromagnetic Induction Motional EMI (Induced Parameter)

Easy

$A$ copper disc of radius $0.1 \, m$ is rotated about its centre with $10 \, rev/s$ in a uniform magnetic field of $0.1 \, T$ with its plane perpendicular to the field. The emf induced across the radius of the disc is ........... $V$.

A
$\frac{\pi}{10}$
B
$\frac{\pi}{100}$
C
$\frac{\pi}{1000}$
D
$0$

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Electromagnetic Induction

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Motional EMI (Induced Parameter)

$A$ conducting rod of length $L$ rotates with angular speed $\omega$ in a uniform magnetic field of induction $B$ which is perpendicular to its motion. The induced emf developed between the two ends of the rod is

DifficultTS EAMCET 2002

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$A$ copper disc of radius $0.1 \ m$ rotates about an axis passing through its centre and perpendicular to its plane with $10 \ \text{revolutions per second}$ in a uniform transverse magnetic field of $0.1 \ T$. The emf induced across the radius of the disc is

DifficultTS EAMCET 2023

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$A$ coil of $n$ turns and area $A$ is placed with its axis parallel to a magnetic field. If the coil is rotated by $180^o$,the charge $Q$ induced in the circuit is given. If the resistance of the circuit is $R$,what is the magnitude of the magnetic field $B$?

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$A$ rod closing the circuit shown in the figure moves along a $U$-shaped wire at a constant speed $v$ under the action of a force $F$. The circuit is in a uniform magnetic field perpendicular to the plane. Calculate $F$ if the rate of heat generation in the circuit is $Q$.

Medium

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$A$ metal rod $AB$ of length $50 \text{ cm}$ is moving at a velocity $8 \text{ ms}^{-1}$ in a magnetic field of $2 \text{ T}$. If the field is at $60^{\circ}$ with the plane of motion as shown in the figure,then the potentials $V_A$ and $V_B$ are related by

MediumAP EAMCET 2019

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$A$ copper disc of radius $0.1 \, m$ is rotated about its centre with $10 \, rev/s$ in a uniform magnetic field of $0.1 \, T$ with its plane perpendicular to the field. The emf induced across the radius of the disc is ........... $V$.

Similar Questions

$A$ conducting rod of length $L$ rotates with angular speed $\omega$ in a uniform magnetic field of induction $B$ which is perpendicular to its motion. The induced emf developed between the two ends of the rod is

$A$ copper disc of radius $0.1 \ m$ rotates about an axis passing through its centre and perpendicular to its plane with $10 \ \text{revolutions per second}$ in a uniform transverse magnetic field of $0.1 \ T$. The emf induced across the radius of the disc is

$A$ coil of $n$ turns and area $A$ is placed with its axis parallel to a magnetic field. If the coil is rotated by $180^o$,the charge $Q$ induced in the circuit is given. If the resistance of the circuit is $R$,what is the magnitude of the magnetic field $B$?

$A$ rod closing the circuit shown in the figure moves along a $U$-shaped wire at a constant speed $v$ under the action of a force $F$. The circuit is in a uniform magnetic field perpendicular to the plane. Calculate $F$ if the rate of heat generation in the circuit is $Q$.

$A$ metal rod $AB$ of length $50 \text{ cm}$ is moving at a velocity $8 \text{ ms}^{-1}$ in a magnetic field of $2 \text{ T}$. If the field is at $60^{\circ}$ with the plane of motion as shown in the figure,then the potentials $V_A$ and $V_B$ are related by

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