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(D) The volume of the cylinder is given by the formula $V = \pi r^2 h$.Given: radius $r = 8\, cm$ and height $h = 2\, cm$.Volume of cylinder $= \pi

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$8$

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(D) The volume of the cylinder is given by the formula $V = \pi r^2 h$.Given: radius $r = 8\, cm$ and height $h = 2\, cm$.Volume of cylinder $= \pi 	imes (8)^2 	imes 2 = 128\pi\, cm^3$.Let the radius of the cone be $r_c$ and its height be $h_c = 6\, cm$.The volume of the cone is given by $V = \frac{1}{3} \pi r_c^2 h_c$.Since the cylinder is melted to form the cone,their volumes are equal:$128\pi = \frac{1}{3} \pi r_c^2 	imes 6$.$128\pi = 2\pi r_c^2$.Dividing both sides by $2\pi$,we get $r_c^2 = 64$.Therefore,$r_c = \sqrt{64} = 8\, cm$.

$A$ cylinder with base radius of $8\, cm$ and height of $2\, cm$ is melted to form a cone of height $6\, cm.$ The radius of the cone will be (in $cm$):

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