A cylindrical resistor is connected across a | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The current $i$ flowing through the resistor is constant throughout its length because it is a series circuit.The relationship between current $i$

Vedclass · Accepted Answer

Vedclass · Answer

(B) The current $i$ flowing through the resistor is constant throughout its length because it is a series circuit.The relationship between current $i$, current density $J$, and drift velocity $V_d$ is given by:$i = J A$$J = n e V_d$Substituting $J$ into the current equation:$i = (n e V_d) A$Since $i$, $n$, and $e$ are constants, we have:$A V_d = 	ext{constant}$$V_d \propto \frac{1}{A}$Since the area $A = \pi r^2$, where $r$ is the radius, we have $V_d \propto \frac{1}{r^2}$.In the middle part of the cylinder, the radius $r$ is larger, so the area $A$ is larger.Therefore, the drift velocity $V_d$ must be smaller in the middle part of the cylinder compared to the ends.This corresponds to the graph where the value of $V_d$ decreases in the region with the larger radius. Graph $B$ shows this behavior.

Similar Questions

Derive the relation between electric current and drift velocity.

The electric intensity $E$,current density $j$,and specific resistance $\rho$ (often denoted as $k$ in some texts) are related to each other by the relation:

$A$ wire has a non-uniform cross-section as shown in the figure. $A$ steady current flows through it. The drift speed of electrons at points $P$ and $Q$ is $v_P$ and $v_Q$ respectively.

The area of cross-section of a copper wire is $4 \times 10^{-7} \,m^2$ and the number of free electrons per cubic metre in copper is $8 \times 10^{28}$. If the wire carries a current of $6.4 \,A$,then the drift velocity of the electrons (in $10^{-3} \,m \,s^{-1}$) is:

The lengths of two wires made of the same material are in the ratio $2:3$ and their radii are in the ratio $1:2$. If the two wires are connected in parallel to a battery,then the ratio of the drift velocities of free electrons in the two wires is

Vedclass Test Series

Exam Paper Generator

Online Exam Module