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(D) This is a binomial distribution problem where $n = 5$ trials are performed.The probability of getting an odd number (success) in a single toss of

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$\frac{5}{4}$

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(D) This is a binomial distribution problem where $n = 5$ trials are performed.The probability of getting an odd number (success) in a single toss of a die is $p = \frac{3}{6} = \frac{1}{2}$.The probability of failure is $q = 1 - p = 1 - \frac{1}{2} = \frac{1}{2}$.The variance of a binomial distribution is given by the formula $	ext{Variance} = npq$.Substituting the values: $	ext{Variance} = 5 	imes \frac{1}{2} 	imes \frac{1}{2} = \frac{5}{4}$.

$A$ die is tossed $5$ times. Getting an odd number is considered a success. Then the variance of the distribution of success is

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