A heavenly body is receding from Earth such t | vedclass

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Question

(A) The Doppler effect for light when a source is receding from an observer is given by the formula $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,whe

Vedclass · Accepted Answer

$C$

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(A) The Doppler effect for light when a source is receding from an observer is given by the formula $\frac{\Delta \lambda}{\lambda} = \frac{v}{c}$,where $\Delta \lambda$ is the change in wavelength,$\lambda$ is the original wavelength,$v$ is the velocity of the source,and $c$ is the speed of light.Given that the fractional change in wavelength $\frac{\Delta \lambda}{\lambda} = 1$.Substituting this into the formula: $1 = \frac{v}{c}$.Therefore,the velocity of the heavenly body is $v = c$.

$A$ heavenly body is receding from Earth such that the fractional change in wavelength $\lambda$ is $1$. What is its velocity?

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