$A$ light ray enters through a right-angled prism at point $P$ with an angle of incidence of $30^{\circ}$ as shown in the figure. It travels through the prism parallel to its base $BC$ and emerges along the face $AC$. The refractive index of the prism is:

  • A
    $\frac{\sqrt{5}}{2}$
  • B
    $\frac{\sqrt{3}}{4}$
  • C
    $\frac{\sqrt{3}}{2}$
  • D
    $\frac{\sqrt{5}}{4}$

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Similar Questions

$A$ ray $OP$ of monochromatic light is incident on the face $AB$ of prism $ABCD$ near vertex $B$ at an incident angle of $60^{\circ}$ (see figure). If the refractive index of the material of the prism is $\sqrt{3}$,which of the following is (are) correct?
$(A)$ The ray gets totally internally reflected at face $CD$
$(B)$ The ray comes out through face $AD$
$(C)$ The angle between the incident ray and the emergent ray is $90^{\circ}$
$(D)$ The angle between the incident ray and the emergent ray is $120^{\circ}$

At the condition of minimum deviation,the angle of emergence is .......

The angle of deviation $\delta$ produced by a prism of refractive index $\mu$ and small refracting angle $A$ is given by:

When light rays are incident on a prism at an angle of $45^o$,the minimum deviation is obtained. If the refractive index of the material of the prism is $\sqrt{2}$,then the angle of the prism will be......$^o$

The refracting angle of a glass prism is $30^{\circ}$. $A$ ray is incident on one of the faces and is perpendicular to it. The angle of deviation $\delta$ between the incident ray and the ray that leaves the prism is (Refractive index of glass $= 1.5$) (Given: $\sin(30^{\circ}) = 0.5, \sin(48.6^{\circ}) = 0.75$). (in $^{\circ}$)

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