A mixture of plane polarised and unpolarised | vedclass

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(A) Let $I_P$ be the intensity of the plane polarized light and $I_0$ be the intensity of the unpolarized light.When light passes through a polarizer,

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$3/2$

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(A) Let $I_P$ be the intensity of the plane polarized light and $I_0$ be the intensity of the unpolarized light.When light passes through a polarizer,the transmitted intensity of the unpolarized component is $I_0/2$.The transmitted intensity of the polarized component is $I_P \cos^2 	heta$,where $	heta$ is the angle between the polarization direction and the transmission axis of the polarizer.The total transmitted intensity is $I(	heta) = I_0/2 + I_P \cos^2 	heta$.The maximum intensity occurs at $	heta = 0$,so $I_{max} = I_0/2 + I_P$.The minimum intensity occurs at $	heta = 90^\circ$,so $I_{min} = I_0/2$.Given that the intensity varies by a factor of $4$,we have $I_{max} / I_{min} = 4$.Substituting the expressions: $(I_0/2 + I_P) / (I_0/2) = 4$.$1 + 2(I_P / I_0) = 4$.$2(I_P / I_0) = 3$.$I_P / I_0 = 3/2$.

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