A particle is moving along the circle x^2 + y | vedclass

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(C) The position vector of the particle at point $P(a \cos 	heta, a \sin 	heta)$ is $\vec{r} = a \cos 	heta \hat{i} + a \sin 	heta \hat{j}$.The un

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$\sin 	heta \hat{i} - \cos 	heta \hat{j}$

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(C) The position vector of the particle at point $P(a \cos 	heta, a \sin 	heta)$ is $\vec{r} = a \cos 	heta \hat{i} + a \sin 	heta \hat{j}$.The unit radial vector is $\hat{r} = \cos 	heta \hat{i} + \sin 	heta \hat{j}$.Since the particle is moving in a circle,the velocity vector $\vec{v}$ is tangent to the circle. The direction of motion is anticlockwise,so the velocity vector is in the direction of $\hat{	heta} = -\sin 	heta \hat{i} + \cos 	heta \hat{j}$.Friction acts in the direction opposite to the velocity of the particle. Therefore,the direction of friction is $-\hat{	heta} = \sin 	heta \hat{i} - \cos 	heta \hat{j}$.

$A$ particle is moving along the circle $x^2 + y^2 = a^2$ in an anticlockwise direction. The $x-y$ plane is a rough horizontal stationary surface. At the point $(a \cos \theta, a \sin \theta)$,the unit vector in the direction of friction on the particle is:

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