A particle moves for 20 ,s with velocity 3 ,m | vedclass

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(B) The average velocity is defined as the total displacement divided by the total time taken.Total displacement $S = S_1 + S_2 + S_3 = (v_1 	imes t_

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(B) The average velocity is defined as the total displacement divided by the total time taken.Total displacement $S = S_1 + S_2 + S_3 = (v_1 	imes t_1) + (v_2 	imes t_2) + (v_3 	imes t_3)$.Given $v_1 = 3 \,m/s$,$v_2 = 4 \,m/s$,$v_3 = 5 \,m/s$ and $t_1 = t_2 = t_3 = 20 \,s$.$S = (3 	imes 20) + (4 	imes 20) + (5 	imes 20) = 60 + 80 + 100 = 240 \,m$.Total time $T = 20 + 20 + 20 = 60 \,s$.Average velocity $v_{avg} = \frac{S}{T} = \frac{240}{60} = 4 \,m/s$.Since the time intervals are equal,the average velocity is simply the arithmetic mean of the velocities: $v_{avg} = \frac{v_1 + v_2 + v_3}{3} = \frac{3 + 4 + 5}{3} = 4 \,m/s$.

$A$ particle moves for $20 \,s$ with velocity $3 \,m/s$,then with velocity $4 \,m/s$ for another $20 \,s$,and finally with velocity $5 \,m/s$ for the next $20 \,s$. What is the average velocity of the particle in $m/s$?

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