$A$ particle of mass $m$ is projected at $45^o$ at $V_0$ speed from point $P$ at $t = 0$. The angular momentum of the particle about $P$ at $t = \frac{V_0}{g}$ is:

  • A
    $\frac{1}{2 \sqrt{2}} \frac{mV_0^3}{g}$
  • B
    $\frac{1}{2 \sqrt{2}} \frac{mV_0^2}{g}$
  • C
    $\frac{1}{2} \frac{mV_0^3}{g}$
  • D
    $\frac{1}{2} \frac{mV_0^2}{g}$

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