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(B) The total time $T$ taken is the sum of the time taken by the stone to fall $(t_1)$ and the time taken by the sound to travel back $(t_2)$.$T = t_1

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(B) The total time $T$ taken is the sum of the time taken by the stone to fall $(t_1)$ and the time taken by the sound to travel back $(t_2)$.$T = t_1 + t_2 = \sqrt{\frac{2L}{g}} + \frac{L}{v}$Given $L = 20 \ m$,$g = 10 \ ms^{-2}$,and $v = 300 \ ms^{-1}$.Differentiating $T$ with respect to $L$:$\frac{dT}{dL} = \frac{1}{2} \sqrt{\frac{2}{gL}} + \frac{1}{v} = \frac{1}{\sqrt{2gL}} + \frac{1}{v}$Substituting the values:$\frac{dT}{dL} = \frac{1}{\sqrt{2 	imes 10 	imes 20}} + \frac{1}{300} = \frac{1}{20} + \frac{1}{300} = \frac{15+1}{300} = \frac{16}{300} \ s/m$Since $\delta T = 0.01 \ s$,we have $\delta L = \delta T / (dT/dL) = 0.01 	imes (300/16) = 3/16 \ m = 0.1875 \ m$.The fractional error is $\frac{\delta L}{L} = \frac{0.1875}{20} = 0.009375$.Percentage error = $0.009375 	imes 100 \% \approx 0.9375 \% \approx 1 \%$.

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