A rectangular coil ABCD is rotated anticlockw | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The magnetic flux $\phi$ linked with the coil is given by $\phi = BA \cos 	heta$,where $	heta$ is the angle between the area vector of the coil

Vedclass · Accepted Answer

The plane of the coil is horizontal

Vedclass · Answer

(A) The magnetic flux $\phi$ linked with the coil is given by $\phi = BA \cos 	heta$,where $	heta$ is the angle between the area vector of the coil and the magnetic field $B$.According to Faraday's law of electromagnetic induction,the induced $e.m.f.$ is $e = -\frac{d\phi}{dt}$.Substituting $\phi = BA \cos(\omega t)$,we get $e = -\frac{d}{dt}(BA \cos(\omega t)) = BA\omega \sin(\omega t)$.Thus,the induced $e.m.f.$ is $e = e_0 \sin(\omega t)$,where $e_0 = BA\omega$ is the maximum $e.m.f.$The $e.m.f.$ is maximum when $\sin(\omega t) = 1$,which occurs when $\omega t = 90^o$.At this position,the area vector is at $90^o$ to the magnetic field,meaning the plane of the coil is parallel to the magnetic field lines.Since the magnetic field is horizontal,the plane of the coil must be horizontal for the induced $e.m.f.$ to be maximum.

$A$ rectangular coil $ABCD$ is rotated anticlockwise with a uniform angular velocity about the axis shown in the diagram below. The axis of rotation of the coil as well as the magnetic field $B$ are horizontal. The induced $e.m.f.$ in the coil would be maximum when

Similar Questions

$A$ straight conductor of length $4 \,m$ moves at a speed of $10 \,m/s$. When the conductor makes an angle of $30^{\circ}$ with the direction of a magnetic field of induction $0.1 \,Wb/m^2$, the induced emf is: (in $\,V$)

$A$ wire of length $1\,m$ is moving with a velocity of $8\,m/s$ at right angles to a magnetic field of $2\,T$. The magnitude of the induced emf between the ends of the wire will be $............\,V$.

The loops have lengths $L$ or $2L$. All loops enter a magnetic field $\vec{B}$ with the same velocity $v$. Which of the following is correct?

The loop shown moves with a velocity $v$ in a uniform magnetic field of magnitude $B$,directed into the paper. The potential difference between $P$ and $Q$ is $e$. Then:

Vedclass Test Series

Exam Paper Generator

Online Exam Module