A semiconductor (Ge - As) has an energy gap o | vedclass

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(C) The energy gap $E_g$ is related to the wavelength $\lambda$ of the emitted photon by the formula: $E_g = \frac{hc}{\lambda}$.Rearranging for $\lam

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$8671$

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(C) The energy gap $E_g$ is related to the wavelength $\lambda$ of the emitted photon by the formula: $E_g = \frac{hc}{\lambda}$.Rearranging for $\lambda$,we get: $\lambda = \frac{hc}{E_g}$.Given $E_g = 1.43\, eV$,$h = 6.63 	imes 10^{-34}\, J\cdot s$,$c = 3 	imes 10^8\, m/s$,and $1\, eV = 1.6 	imes 10^{-19}\, J$.Using the shortcut formula $\lambda (	ext{in } \mathring{A}) = \frac{12400}{E_g (	ext{in } eV)}$:$\lambda = \frac{12400}{1.43} \approx 8671.3\, \mathring{A}$.Thus,the maximum wavelength is approximately $8671\, \mathring{A}$.

$A$ semiconductor $(Ge - As)$ has an energy gap of $1.43\, eV.$ What is the maximum wavelength emitted when a hole and an electron recombine in such semiconductor in $\mathring{A}$?

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