A slab of glass,of thickness 6, cm and refrac | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When an object is placed in front of a concave mirror such that the reflected image coincides with the object,the rays must strike the mirror norm

Vedclass · Accepted Answer

$42$

Vedclass · Answer

(C) When an object is placed in front of a concave mirror such that the reflected image coincides with the object,the rays must strike the mirror normally. This means the rays must appear to come from the center of curvature $C$ of the mirror after passing through the glass slab.Let the distance of the object from the mirror be $u$. The glass slab causes a normal shift $\Delta x$ in the position of the object,given by $\Delta x = t \left( 1 - \frac{1}{\mu} \right)$,where $t = 6\, cm$ and $\mu = 1.5$.$\Delta x = 6 \left( 1 - \frac{1}{1.5} \right) = 6 \left( 1 - \frac{2}{3} \right) = 6 \left( \frac{1}{3} \right) = 2\, cm$.The apparent position of the object must coincide with the center of curvature $C$ of the mirror. The distance of the center of curvature from the mirror is equal to the radius of curvature $R = 40\, cm$.Therefore,the apparent distance of the object from the mirror is $40\, cm$.The actual distance of the object from the mirror is $u = R + \Delta x = 40\, cm + 2\, cm = 42\, cm$.

Similar Questions

$A$ rectangular glass block is placed on a mark made on the surface of a table and is viewed from a vertical direction. If the refractive index of the glass is $\mu$ and its thickness is $d$,by what distance will the mark appear to be raised?

White light is incident normally on a glass slab. Inside the glass slab,

$A$ microscope is focused on a mark on a piece of paper and then a slab of glass of thickness $3\, cm$ and refractive index $1.5$ is placed over the mark. How should the microscope be moved to get the mark in focus again?

Vedclass Test Series

Exam Paper Generator

Online Exam Module