(B) Let $A$ be benzene and $B$ be toluene. Given: $P^o_A = 74.7\,torr$,$P^o_B = 22.3\,torr$,$n_A = 1.5\,mol$,$n_B = 3.5\,mol$. Total moles $n_{total}

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(B) Let $A$ be benzene and $B$ be toluene. Given: $P^o_A = 74.7\,torr$,$P^o_B = 22.3\,torr$,$n_A = 1.5\,mol$,$n_B = 3.5\,mol$. Total moles $n_{total} = 1.5 + 3.5 = 5.0\,mol$. Mole fraction of benzene in liquid phase,$x_A = \frac{1.5}{5.0} = 0.3$. Mole fraction of toluene in liquid phase,$x_B = \frac{3.5}{5.0} = 0.7$. Total vapour pressure of the solution,$P_{total} = P^o_A x_A + P^o_B x_B = (74.7 \times 0.3) + (22.3 \times 0.7) = 22.41 + 15.61 = 38.02\,torr \approx 38.0\,torr$. Mole fraction of benzene in vapour phase $(y_A)$ is given by $y_A = \frac{P_A}{P_{total}} = \frac{P^o_A x_A}{P_{total}} = \frac{22.41}{38.02} \approx 0.589$.

Class 12 Chemistry Solutions Mix Examples of Solutions

$A$ solution at $20\,^oC$ is composed of $1.5\,mol$ of benzene and $3.5\,mol$ of toluene. If the vapour pressure of pure benzene and pure toluene at this temperature are $74.7\,torr$ and $22.3\,torr,$ respectively,then the total vapour pressure of the solution and the benzene mole fraction in equilibrium with it will be,respectively

JEE MAIN 2015 All JEE MAIN

A
$35.8\,torr$ and $0.280$
B
$38.0\,torr$ and $0.589$
C
$30.5\,torr$ and $0.389$
D
$30.5\,torr$ and $0.480$

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$A$ solution containing $1.8 \ g$ of a compound (empirical formula $CH_2O$) in $40 \ g$ of water is observed to freeze at $-0.465 \ ^oC$. The molecular formula of the compound is ($K_f$ of water $= 1.86 \ K \ kg \ mol^{-1}$)

MediumAIIMS 2016

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The elevation in the boiling point of an aqueous urea solution is $0.104 \ K$. What is its $\Delta T_{f}$ (in $K$) value? (Given for water: $K_{b} = 0.52 \ K \ kg \ mol^{-1}$,$K_{f} = 1.86 \ K \ kg \ mol^{-1}$)

EasyAP EAMCET 2023

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$A$ solution of urea (molar mass $60 \ g \ mol^{-1}$) boils at $100.20^{\circ}C$ at atmospheric pressure. If $K_{f}$ and $K_{b}$ for water are $1.86$ and $0.512 \ K \ kg \ mol^{-1}$ respectively,the freezing point of the solution will be:

MediumAP EAMCET 2021

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Benzene and naphthalene form an ideal solution at room temperature. For this process,the true statement$(s)$ is (are)
$(A)$ $\Delta G$ is positive
$(B)$ $\Delta S_{\text{system}}$ is positive
$(C)$ $\Delta S_{\text{surroundings}} = 0$
$(D)$ $\Delta H = 0$

MediumIIT 2013

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Match List-$I$ with List-$II$

List-$I$ List-$II$

$A$. Solution of chloroform and acetone $I$. Minimum boiling azeotrope

$B$. Solution of ethanol and water $II$. Dimerizes

$C$. Solution of benzene and toluene $III$. Maximum boiling azeotrope

$D$. Solution of acetic acid in benzene $IV$. $\Delta V_{mix}=0$

Choose the correct answer from the options given below $:$

MediumJEE MAIN 2025

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List-$I$	List-$II$
$A$. Solution of chloroform and acetone	$I$. Minimum boiling azeotrope
$B$. Solution of ethanol and water	$II$. Dimerizes
$C$. Solution of benzene and toluene	$III$. Maximum boiling azeotrope
$D$. Solution of acetic acid in benzene	$IV$. $\Delta V_{mix}=0$

Similar Questions

$A$ solution containing $1.8 \ g$ of a compound (empirical formula $CH_2O$) in $40 \ g$ of water is observed to freeze at $-0.465 \ ^oC$. The molecular formula of the compound is ($K_f$ of water $= 1.86 \ K \ kg \ mol^{-1}$)

The elevation in the boiling point of an aqueous urea solution is $0.104 \ K$. What is its $\Delta T_{f}$ (in $K$) value? (Given for water: $K_{b} = 0.52 \ K \ kg \ mol^{-1}$,$K_{f} = 1.86 \ K \ kg \ mol^{-1}$)

$A$ solution of urea (molar mass $60 \ g \ mol^{-1}$) boils at $100.20^{\circ}C$ at atmospheric pressure. If $K_{f}$ and $K_{b}$ for water are $1.86$ and $0.512 \ K \ kg \ mol^{-1}$ respectively,the freezing point of the solution will be:

Benzene and naphthalene form an ideal solution at room temperature. For this process,the true statement$(s)$ is (are)$(A)$ $\Delta G$ is positive$(B)$ $\Delta S_{\text{system}}$ is positive$(C)$ $\Delta S_{\text{surroundings}} = 0$$(D)$ $\Delta H = 0$

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Benzene and naphthalene form an ideal solution at room temperature. For this process,the true statement$(s)$ is (are)
$(A)$ $\Delta G$ is positive
$(B)$ $\Delta S_{\text{system}}$ is positive
$(C)$ $\Delta S_{\text{surroundings}} = 0$
$(D)$ $\Delta H = 0$