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(A) The net work done in a cyclic process is equal to the area enclosed by the cycle on a $P-V$ diagram. The area of the rectangle $PQRS$ is given by

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$20$

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(A) The net work done in a cyclic process is equal to the area enclosed by the cycle on a $P-V$ diagram. The area of the rectangle $PQRS$ is given by $	ext{Area} = 	ext{width} 	imes 	ext{height}$. Here,$	ext{width} = \Delta V = (3 - 1) 	imes 10^{-3} \ m^3 = 2 	imes 10^{-3} \ m^3$ and $	ext{height} = \Delta P = (20 - 10) 	imes 10^3 \ Pa = 10 	imes 10^3 \ Pa$. The work done $W = P \Delta V = (10 	imes 10^3) 	imes (2 	imes 10^{-3}) = 20 \ J$. Since the cycle is traversed in a clockwise direction,the work done by the system is positive.

$A$ thermodynamic system is taken through the cycle $PQRS P$ process. The net work done by the system is ....... $J$. (Note: Assuming a standard $P-V$ diagram where $P$ is in $kPa$ and $V$ is in $m^3$,with vertices $P(1, 10)$,$Q(3, 10)$,$R(3, 20)$,$S(1, 20)$)

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