$A$ transistor is operated in common emitter configuration at a constant collector voltage $V_C = 1.5 \, V$ such that a change in the base current from $100 \, \mu A$ to $150 \, \mu A$ produces a change in the collector current from $5 \, mA$ to $10 \, mA$. The current gain $\beta$ is:

For a common emitter configuration,if $\alpha$ and $\beta$ have their usual meanings,the incorrect relationship between $\alpha$ and $\beta$ is:

In a common emitter configuration with suitable bias,it is given that $R_L$ is the load resistance and $R_{BE}$ is the small signal dynamic resistance (input side). Then,the voltage gain,current gain,and power gain are given,respectively,by: [$\beta$ is the current gain,$I_B$,$I_C$,$I_E$ are respectively base,collector,and emitter currents]

For a transistor amplifier,the power gain and voltage gain are $7.5$ and $2.5$ respectively. The value of the current gain will be:

Assertion : In a common emitter transistor amplifier,the input current is much less than the output current.
Reason : The common emitter transistor amplifier has very high input impedance.

In a common emitter $(CE)$ amplifier having a voltage gain $G$,the transistor used has a transconductance of $0.03\,mho$ and a current gain of $25$. If the above transistor is replaced with another one with a transconductance of $0.02\,mho$ and a current gain of $20$,the new voltage gain will be: