$A$ vector $\vec Q$ which has a magnitude of $8$ is added to the vector $\vec P$ which lies along the $x$-axis. The resultant of the two vectors lies along the $y$-axis and has a magnitude twice that of $\vec P$. The magnitude of $\vec P$ is:

  • A
    $\frac {6}{\sqrt 5}$
  • B
    $\frac {8}{\sqrt 5}$
  • C
    $\frac {12}{\sqrt 5}$
  • D
    $\frac {16}{\sqrt 5}$

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