Addition of powdered lead and iron to a solution which is $1.0 \, M$ in both $Pb^{2+}$ and $Fe^{2+}$ would result in [$E^{\circ}_{Fe^{2+}/Fe} = -0.44 \, V$ and $E^{\circ}_{Pb^{2+}/Pb} = -0.13 \, V$]

• A
  Increase in concentrations of both $Pb^{2+}$ and $Fe^{2+}$ ions
• B
  Decrease in concentrations of $Pb^{2+}$ and $Fe^{2+}$ ions
• C
  $Pb^{2+}$ concentration increases and $Fe^{2+}$ concentration decreases
• D
  $Fe^{2+}$ concentration increases and $Pb^{2+}$ concentration decreases