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Question

(C) The additive inverse of a complex number $z$ is a number $-z$ such that $z + (-z) = 0$.Let the additive inverse of $z = 1 - i$ be $z' = x + iy$.Th

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$-1 + i$

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(C) The additive inverse of a complex number $z$ is a number $-z$ such that $z + (-z) = 0$.Let the additive inverse of $z = 1 - i$ be $z' = x + iy$.Then,$(1 - i) + (x + iy) = 0$.$(1 + x) + i(y - 1) = 0 + 0i$.Comparing real and imaginary parts,we get $1 + x = 0$ and $y - 1 = 0$.Thus,$x = -1$ and $y = 1$.Therefore,the additive inverse is $z' = -1 + i$.Hence,the correct option is $C$.

The additive inverse of $1 - i$ is

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