Among the following compounds $I-IV$,which one forms a yellow precipitate on reacting sequentially with $(i)$ $NaOH$,$(ii)$ dil. $HNO_{3}$,and $(iii)$ $AgNO_{3}$?

For the following compounds,the correct statement$(s)$ with respect to nucleophilic substitution reactions is(are):
$I$: Benzyl bromide $(C_6H_5CH_2Br)$
$II$: Cyclohexylmethyl bromide $(C_6H_{11}CH_2Br)$
$III$: tert-Butyl bromide $((CH_3)_3CBr)$
$IV$: $1-$Phenylethyl bromide $(C_6H_5CH(CH_3)Br)$
$A$. $I$ and $III$ follow $S_{N}1$ mechanism
$B$. $I$ and $II$ follow $S_{N}2$ mechanism
$C$. Compound $IV$ undergoes inversion of configuration
$D$. The order of reactivity for $I$,$III$ and $IV$ is: $IV > I > III$

The products $A$ and $B$ formed in the above reactions are

The decreasing order of reactivity of the following organic molecules towards $AgNO_3$ solution is:

Compound $C_4H_8Cl_2$ $(A)$ on hydrolysis gives a compound $C_4H_8O$ $(B)$ which reacts with hydroxylamine and does not give any test with Tollen's reagent. What are $(A)$ and $(B)$?

Arrange the following bromides in the order of reactivity in undergoing $S_{N}1$ reaction:
$(i)$ $(CH_3)_3CBr$
(ii) $CH_3CH_2CH_2Br$
(iii) $(CH_3)_2CHCH_2Br$
(iv) $CH_3Br$