An ac current is represented as i = 5 sqrt{2} | vedclass

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(C) The given current is $i = 5 \sqrt{2} + 10 \cos \left(650 \pi t + \frac{\pi}{6}\right)$.To find the $r.m.s$ value,we use the formula $I_{rms} = \sq

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$10 	ext{ A}$

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(C) The given current is $i = 5 \sqrt{2} + 10 \cos \left(650 \pi t + \frac{\pi}{6}ight)$.To find the $r.m.s$ value,we use the formula $I_{rms} = \sqrt{\langle i^2 angle}$.First,calculate $i^2 = \left(5 \sqrt{2} + 10 \cos \left(650 \pi t + \frac{\pi}{6}ight)ight)^2$.$i^2 = (5 \sqrt{2})^2 + (10 \cos \left(650 \pi t + \frac{\pi}{6}ight))^2 + 2(5 \sqrt{2})(10 \cos \left(650 \pi t + \frac{\pi}{6}ight))$.$i^2 = 50 + 100 \cos^2 \left(650 \pi t + \frac{\pi}{6}ight) + 100 \sqrt{2} \cos \left(650 \pi t + \frac{\pi}{6}ight)$.Taking the average over a full cycle,$\langle \cos 	heta angle = 0$ and $\langle \cos^2 	heta angle = \frac{1}{2}$.$\langle i^2 angle = 50 + 100 \left(\frac{1}{2}ight) + 0 = 50 + 50 = 100$.Therefore,$I_{rms} = \sqrt{100} = 10 	ext{ A}$.

An $ac$ current is represented as $i = 5 \sqrt{2} + 10 \cos \left(650 \pi t + \frac{\pi}{6}\right) \text{ A}$. The $r.m.s$ value of the current is:

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