An e.m.f. of 12 , V is produced in a coil whe | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The induced $e.m.f.$ $(e)$ in a coil is given by the formula: $e = L \cdot \frac{di}{dt}$.Here,$e = 12 \, V$.The rate of change of current is $\fr

Vedclass · Accepted Answer

$16$

Vedclass · Answer

(D) The induced $e.m.f.$ $(e)$ in a coil is given by the formula: $e = L \cdot \frac{di}{dt}$.Here,$e = 12 \, V$.The rate of change of current is $\frac{di}{dt} = 45 \, A/min$.First,convert the rate of change of current into $A/s$:$\frac{di}{dt} = \frac{45 \, A}{60 \, s} = 0.75 \, A/s$.Now,substitute the values into the formula:$12 = L 	imes 0.75$.$L = \frac{12}{0.75} = \frac{1200}{75} = 16 \, H$.Therefore,the inductance of the coil is $16 \, H$.

An $e.m.f.$ of $12 \, V$ is produced in a coil when the current in it changes at the rate of $45 \, A/min$. The inductance of the coil is ....... $H$.

Similar Questions

The current passing through a choke coil of $5 \, H$ is decreasing at the rate of $2 \, A/s$. The $e.m.f.$ developed across the coil is ....... $V$.

When current in a coil changes from $2 \ A$ to $5 \ A$ in a time of $0.3 \ s$,if the emf induced in the coil is $40 \ mV$,then the self inductance of the coil is

$A$ coil of wire of radius $r$ has $600$ turns and self-inductance of $108 \ mH$. The self-inductance of a coil with the same radius and $500$ turns is (in $mH$)

The self-inductance of a solenoid is:

$A$ coil of self-inductance $L$ is connected in series with a bulb and an a.c. source. Brightness of the bulb decreases when

Vedclass Test Series

Exam Paper Generator

Online Exam Module