An achromatic prism is made by combining two | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For an achromatic combination of two prisms,the net dispersion must be zero.The condition for zero net dispersion is given by: $A(\mu_v - \mu_r) +

Vedclass · Accepted Answer

$5$

Vedclass · Answer

(A) For an achromatic combination of two prisms,the net dispersion must be zero.The condition for zero net dispersion is given by: $A(\mu_v - \mu_r) + A'(\mu'_v - \mu'_r) = 0$.Here,$A = 10^o$,$\mu_v - \mu_r = 1.523 - 1.515 = 0.008$,and $\mu'_v - \mu'_r = 1.666 - 1.650 = 0.016$.Substituting these values into the equation:$10^o(0.008) + A'(0.016) = 0$.$0.08 + A'(0.016) = 0$.$A'(0.016) = -0.08$.$A' = -\frac{0.08}{0.016} = -5^o$.The magnitude of the prism angle is $5^o$ (the negative sign indicates that the second prism must be oriented in the opposite direction to the first).

An achromatic prism is made by combining two prisms $P_1$ $(\mu_v = 1.523, \mu_r = 1.515)$ and $P_2$ $(\mu'_v = 1.666, \mu'_r = 1.650)$,where $\mu$ represents the refractive index. If the angle of the prism $P_1$ is $10^o$,then the angle of the prism $P_2$ will be.....$^o$

Similar Questions

When white light passes through an achromatic combination of prisms,what is observed?

The figure shows the graph of the angle of deviation $\delta$ versus the angle of incidence $i$ for a light ray striking a prism. The prism angle $A$ is: (in $^{\circ}$)

The graph between angle of deviation $(\delta)$ and angle of incidence $(i)$ for a triangular prism is represented by :-

For a thin prism,if the angle of prism is $4^{\circ}$ and the refractive index is $1.6$,then the angle of minimum deviation will be . . . . . . . (in $^{\circ}$)

If the refractive index of the material of a prism is $\cot(A/2)$,where $A$ is the angle of the prism,then the angle of minimum deviation will be:

Vedclass Test Series

Exam Paper Generator

Online Exam Module