An electric field is given by $\vec{E} = (6 \hat{i} + 5 \hat{j} + 3 \hat{k}) \ N/C$. The electric flux through a surface area $\vec{A} = 30 \hat{i} \ m^2$ (in $SI$ units) is:

The electric field ( $\overrightarrow{E}$ in $N C^{-1}$ ) in a region is given by $\overrightarrow{E} = 3 \hat{i} + 5 \hat{j}$. The net electric flux through a square area of side $2 \ m$ parallel to the $y-z$ plane is:

You are given a dipole of charge $+q$ and $-q$ separated by a distance $2R$. $A$ sphere '$A$' of radius ' $R$ ' passes through the centre of the dipole as shown below and another sphere '$B$' of radius ' $2R$ ' passes through the charge $+q$. Then the electric flux through the sphere '$A$' is

The figure shows the electric lines of force emerging from a charged body. If the electric field at $A$ and $B$ are $E_A$ and $E_B$ respectively,and if the distance between $A$ and $B$ is $r$,then:

If $\vec E = \frac{E_0 x}{a} \hat i$,then find the electric flux through the shaded area of the cube as shown in the figure,where the shaded face is at $x = a$.

$A$ charge $Q \ C$ is placed at the center of a cube. If $\varepsilon_0$ is the permittivity of vacuum,then the flux through one face and two opposite faces of the cube is respectively: