The figure shows the electric lines of force emerging from a charged body. If the electric field at $A$ and $B$ are $E_A$ and $E_B$ respectively,and if the distance between $A$ and $B$ is $r$,then:

  • A
    $E_A > E_B$
  • B
    $E_A < E_B$
  • C
    $E_A = \frac{E_B}{r}$
  • D
    $E_A = \frac{E_B}{r^2}$

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Similar Questions

Select the correct statement$(s)$.
$(1)$ The tangent drawn at any point on an electric field line gives the direction of the force acting on a positive charge at that point.
$(2)$ The normal drawn at any point on an electric field line gives the direction of the force acting on a positive charge at that point.
$(3)$ Electric field lines start from a negative charge and end on a positive charge.
$(4)$ Electric field lines start from a positive charge and end on a negative charge.

$A$ square surface of side $L \; m$ in the plane of the paper is placed in a uniform electric field $E \; (V/m)$ acting along the same plane at an angle $\theta$ with the horizontal side of the square as shown in the figure. The electric flux linked to the surface,in units of $V \cdot m$,is:

If the number of electric lines of force emerging out of a closed surface is $1000$,then the charge enclosed by the surface is .......... $C$.

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The figure shows electric field lines due to a charge configuration. From this,we conclude that:

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