An equilateral triangle $OAB$ is inscribed in the parabola $y^{2}=4x$ with the vertex $O$ at the origin. Then the minimum distance of the circle having $AB$ as a diameter from the origin is:

  • A
    $4(3-\sqrt{3})$
  • B
    $2(8-3\sqrt{3})$
  • C
    $4(6+\sqrt{3})$
  • D
    $2(3+\sqrt{3})$

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