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(C) According to Gay-Lussac's Law,for a fixed volume of gas,pressure is directly proportional to temperature: $\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2

Vedclass · Accepted Answer

$927$

Vedclass · Answer

(C) According to Gay-Lussac's Law,for a fixed volume of gas,pressure is directly proportional to temperature: $\frac{P_{1}}{T_{1}} = \frac{P_{2}}{T_{2}}$.Given: $P_{1} = 300 \ kPa = 300 	imes 10^{3} \ Pa$,$T_{1} = 27 + 273 = 300 \ K$,$P_{2} = 1.2 	imes 10^{6} \ Pa$.Substituting the values: $\frac{300 	imes 10^{3}}{300} = \frac{1.2 	imes 10^{6}}{T_{2}}$.$1000 = \frac{1.2 	imes 10^{6}}{T_{2}} \Rightarrow T_{2} = \frac{1.2 	imes 10^{6}}{1000} = 1200 \ K$.Converting to Celsius: $T(^{\circ} C) = 1200 - 273 = 927^{\circ} C$.

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