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(D) For an astronomical telescope in normal adjustment,the length of the tube $L$ is given by the sum of the focal lengths of the objective lens $(f_o

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$45 \ cm$ and $5 \ cm$

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(D) For an astronomical telescope in normal adjustment,the length of the tube $L$ is given by the sum of the focal lengths of the objective lens $(f_o)$ and the eyepiece $(f_e)$: $L = f_o + f_e$. Given $L = 50 \ cm$,we have $f_o + f_e = 50 \ cm$. For an astronomical telescope,both the objective and the eyepiece are convex lenses,meaning their focal lengths are positive. Additionally,for high magnification,the objective focal length $f_o$ is typically much larger than the eyepiece focal length $f_e$. Comparing the options,$f_o = 45 \ cm$ and $f_e = 5 \ cm$ satisfies $f_o + f_e = 50 \ cm$ and both are positive.

An object is clearly seen through an astronomical telescope of length $50 \ cm$. The focal lengths of its objective and eyepiece,respectively,can be

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