An object is initially at a distance of $100 \; cm$ from a plane mirror. If the mirror approaches the object at a speed of $10 \; cm/s$,then after $6 \; s$,the distance between the object and its image will be: (in $; cm$)

$A$ watch shows time as $3:25$ when seen through a mirror,the time appeared will be

Two vertical parallel mirrors $A$ and $B$ are separated by $10\,cm$. $A$ point object $O$ is placed at a distance of $2\,cm$ from mirror $A$. The distance of the second nearest image behind mirror $A$ from the mirror $A$ is $.........\,cm$.

Two mirrors,labeled $LM$ for left mirror and $RM$ for right mirror in the adjacent figure,are parallel to each other and $3.0 \, m$ apart. $A$ person standing $1.0 \, m$ from the right mirror $(RM)$ looks into this mirror and sees a series of images. How far from the person is the second closest image seen in the right mirror $(RM)$ (in $, m$)?

$A$ plane mirror makes an angle of $30^\circ$ with the horizontal. If a vertical ray strikes the mirror,find the angle between the mirror and the reflected ray.

Two plane mirrors ${M}_{1}$ and ${M}_{2}$ are at a right angle to each other as shown. $A$ point source $P$ is placed at distances of $a$ and $2a$ meters from ${M}_{1}$ and ${M}_{2}$ respectively. The longest distance between the images thus formed is: (Take $\sqrt{5} = 2.3$)