Arrange the following in increasing order of their basic strength:
$(i)$ $C_2H_5NH_2, C_6H_5NH_2, NH_3, C_6H_5CH_2NH_2$ and $(C_2H_5)_2NH$
$(ii)$ $C_2H_5NH_2, (C_2H_5)_2NH, (C_2H_5)_3N, C_6H_5NH_2$
$(iii)$ $CH_3NH_2, (CH_3)_2NH, (CH_3)_3N, C_6H_5NH_2, C_6H_5CH_2NH_2$

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(N/A) $(i)$ Considering the inductive effect of alkyl groups,the basic strength order is $C_6H_5NH_2 < NH_3 < C_6H_5CH_2NH_2 < C_2H_5NH_2 < (C_2H_5)_2NH$.
$(ii)$ Considering the inductive effect,solvation effect,and steric hindrance of the alkyl groups in aqueous medium,the order is $C_6H_5NH_2 < C_2H_5NH_2 < (C_2H_5)_3N < (C_2H_5)_2NH$.
$(iii)$ Considering the inductive effect,solvation effect,and steric hindrance of the methyl groups in aqueous medium,the order is $C_6H_5NH_2 < C_6H_5CH_2NH_2 < (CH_3)_3N < CH_3NH_2 < (CH_3)_2NH$.

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