Which one of the following amides will not undergo the Hoffmann bromamide reaction?

Reduction of nitrobenzene with zinc $(Zn)$ and ammonium chloride $(NH_4Cl)$ gives:

Identify product $B$ in the following reaction: $Aniline$ $\xrightarrow{NaNO_2 + HCl, 273 \ K} A$ $\xrightarrow{H_2O, \Delta} B + N_2 \uparrow$

$A$ student has been given a compound $x$ of molecular formula $C_6H_7N$. $x$ is sparingly soluble in water. However, on addition of dilute mineral acid, $x$ becomes soluble in water. $x$ when treated with $CHCl_3$ and $KOH$ (alc.) produces $y$. $y$ has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, $x$ gives a compound $z$ which is soluble in alkali. The number of different $H$ atoms present in $z$ is:

Given below are two statements:
Statement $I$: Aniline is less basic than acetamide.
Statement $II$: In aniline,the lone pair of electrons on nitrogen atom is delocalised over benzene ring due to resonance and hence less available to a proton.
Choose the most appropriate option:

In the given reaction,identify the reagent $A$:
$4-nitro-3-bromobenzenediazonium \ chloride \xrightarrow{A} 1-bromo-3-nitrobenzene$