(C) Low spin complexes are formed when strong field ligands cause pairing of electrons,resulting in a smaller number of unpaired electrons.In $[FeF_6]

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

If the Assertion is correct but Reason is incorrect.

(C) Low spin complexes are formed when strong field ligands cause pairing of electrons,resulting in a smaller number of unpaired electrons.In $[FeF_6]^{3-}$,the oxidation state of $Fe$ is $+3$ ($3d^5$ configuration).$F^{-}$ is a weak field ligand,which does not cause pairing of electrons.Therefore,$[FeF_6]^{3-}$ is a high spin complex with $5$ unpaired electrons.Thus,the Assertion is correct,but the Reason is incorrect.

Class 12 Chemistry Coordination Compounds Complexes and complex stability

Medium

Assertion : Low spin complexes have lesser number of unpaired electrons.
Reason : $[FeF_6]^{3-}$ is a low spin complex.

AIIMS 2011 All AIIMS

A
If both Assertion and Reason are correct and the Reason is a correct explanation of the Assertion.
B
If both Assertion and Reason are correct but Reason is not a correct explanation of the Assertion.
C
If the Assertion is correct but Reason is incorrect.
D
If both the Assertion and Reason are incorrect.

Explore More

Browse All

Question Bank

All Subjects

Class 12 Questions

Class 12

Chemistry Questions

Chapter

Coordination Compounds

Subtopic

Complexes and complex stability

Previous Year

AIIMS 2011 Paper All AIIMS years →

If an excess of $NH_4OH$ is added to a $CuSO_4$ solution,it forms a deep blue coloured complex which is:

Medium

View Solution

Which among the following cations will form the lowest stability complex if the ligand remains the same?

EasyMHT CET 2021

View Solution

Aqueous copper sulphate solution (blue in colour) gives:
$(i)$ a green precipitate with aqueous potassium fluoride,and
$(ii)$ a bright green solution with aqueous potassium chloride
Explain these experimental results.

Medium

View Solution

Assign $A, B, C, D$ for the given type of reaction: $Fe(CN)_3 \downarrow + 3KCN \longrightarrow K_3[Fe(CN)_6]$

Medium

View Solution

If $1/3$ of the total chlorine in the compound is precipitated on adding $AgNO_3$ to its aqueous solution,which of the following is the correct structure of $CrCl_3 \cdot 6H_2O$?

Medium

View Solution

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial

For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free

For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo

Assertion : Low spin complexes have lesser number of unpaired electrons.Reason : $[FeF_6]^{3-}$ is a low spin complex.

Similar Questions

If an excess of $NH_4OH$ is added to a $CuSO_4$ solution,it forms a deep blue coloured complex which is:

Which among the following cations will form the lowest stability complex if the ligand remains the same?

Aqueous copper sulphate solution (blue in colour) gives:$(i)$ a green precipitate with aqueous potassium fluoride,and$(ii)$ a bright green solution with aqueous potassium chlorideExplain these experimental results.

Assign $A, B, C, D$ for the given type of reaction: $Fe(CN)_3 \downarrow + 3KCN \longrightarrow K_3[Fe(CN)_6]$

If $1/3$ of the total chlorine in the compound is precipitated on adding $AgNO_3$ to its aqueous solution,which of the following is the correct structure of $CrCl_3 \cdot 6H_2O$?

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Assertion : Low spin complexes have lesser number of unpaired electrons.
Reason : $[FeF_6]^{3-}$ is a low spin complex.

Aqueous copper sulphate solution (blue in colour) gives:
$(i)$ a green precipitate with aqueous potassium fluoride,and
$(ii)$ a bright green solution with aqueous potassium chloride
Explain these experimental results.