Atomic numbers of Cr,Fe,and Co are 24,26,and | vedclass

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(D) To determine which complex is paramagnetic,we analyze the electronic configuration of the central metal ion in each complex:$1$. $[Co(NH_3)_6]^{3+

Vedclass · Accepted Answer

$[Cr(CN)_6]^{3-}$

Vedclass · Answer

(D) To determine which complex is paramagnetic,we analyze the electronic configuration of the central metal ion in each complex:$1$. $[Co(NH_3)_6]^{3+}$: $Co^{3+}$ is $3d^6$. $NH_3$ is a strong field ligand,causing pairing. All electrons are paired $(t_{2g}^6 e_g^0)$,so it is diamagnetic.$2$. $[Co(CN)_6]^{3-}$: $Co^{3+}$ is $3d^6$. $CN^-$ is a strong field ligand,causing pairing. All electrons are paired $(t_{2g}^6 e_g^0)$,so it is diamagnetic.$3$. $[Fe(CN)_6]^{4-}$: $Fe^{2+}$ is $3d^6$. $CN^-$ is a strong field ligand,causing pairing. All electrons are paired $(t_{2g}^6 e_g^0)$,so it is diamagnetic.$4$. $[Cr(CN)_6]^{3-}$: $Cr^{3+}$ is $3d^3$. The configuration is $t_{2g}^3 e_g^0$. There are $3$ unpaired electrons in the $3d$ orbitals. Thus,it is paramagnetic.Therefore,the correct option is $D$.

Atomic numbers of $Cr$,$Fe$,and $Co$ are $24$,$26$,and $27$ respectively. Which of the following inner orbital octahedral complexes are paramagnetic?

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