Bonding in which of the following diatomic molecule$(s)$ becomes stronger,on the basis of $M.O.$ Theory,by removal of an electron?
$(A)$ $NO$
$(B)$ $N_2$
$(C)$ $O_2$
$(D)$ $C_2$
$(E)$ $B_2$
Choose the most appropriate answer from the options given below.

  • A
    $(A), (C)$ only
  • B
    $(B), (C), (E)$ only
  • C
    $(A), (B), (C)$ only
  • D
    $(D)$ only

Explore More

Similar Questions

Which of the following pairs of species have the same number of unpaired electrons but different bond orders?

Provide the energy level diagram obtained by the overlapping of $2p_{z}$ orbitals and show the diagram of the resulting molecular orbitals.

Which one of the following constitutes a group of the isoelectronic species?

Match the following:
Pair of species Identical property
$A$. $B_2 \& O_2$ $P$. Bond order $= 2.5$
$B$. $Be_2 \& H_2^{2-}$ $Q$. Paramagnetic nature
$C$. $N_2^{+} \& N_2^{-}$ $R$. Diamagnetic nature
$D$. $O_2^{+} \& O_2^{-}$ $S$. Doesn't exist

According to $MO$ theory,which of the following lists ranks the nitrogen species in terms of increasing bond order?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo