Clemmensen reduction of ketones is carried out in

  • A
    $H_2$ with $Pd$ catalyst
  • B
    Glycol with $KOH$
  • C
    $LiAlH_4$ in water
  • D
    $Zn-Hg$ with $HCl$

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In the given reaction,what will be $A$ and $B$ respectively?
$(CH_3)_2CO$ $\xrightarrow{NaCN/HCl} A$ $\xrightarrow{H_3O^+} B$

Which of the following compounds containing a carbonyl group will give a coloured crystalline compound with $2, 4-DNP$?

The molecular formula of compound $A$ is $C_2Cl_3OH$. It reduces Fehling's solution and on oxidation gives a monocarboxylic acid $B$. Compound $A$ is obtained by the reaction of chlorine with ethyl alcohol. What is $A$?

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The Clemmensen reduction of acetone yields

The major product formed in the reaction is

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