Complete oxidation of 1 gram molecule of gluc | vedclass

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Question

(B) The complete aerobic oxidation of $1$ mole (gram molecule) of glucose $(C_6H_{12}O_6)$ releases approximately $686,000$ calories ($686$ $kcal$) of

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$686,000$ $cal$

Vedclass · Answer

(B) The complete aerobic oxidation of $1$ mole (gram molecule) of glucose $(C_6H_{12}O_6)$ releases approximately $686,000$ calories ($686$ $kcal$) of energy.In anaerobic respiration,$1$ molecule of glucose yields only $56$ $kcal$ ($2$ $ATP$ equivalent).In aerobic respiration,the complete breakdown of $1$ molecule of glucose results in the production of $38$ $ATP$ molecules,releasing a total of $686$ $kcal$ of energy.

Complete oxidation of $1$ gram molecule of glucose gives rise to:

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