Consider a thin metal strip of mass $1 \, kg$ and length $5 \, m$. Calculate its moment of inertia about an axis perpendicular to the strip and located at $100 \, cm$ on the strip from one of its ends. (Assume the breadth of the strip is negligible.)

Four holes of radius $R$ are cut from a thin square plate of side $4R$ and mass $M$. The moment of inertia of the remaining portion about the $z-$ axis is

Four solid spheres,each of diameter $\sqrt{5} \ cm$ and mass $0.5 \ kg$,are placed with their centers at the corners of a square of side $4 \ cm$. The moment of inertia of the system about the diagonal of the square is $N \times 10^{-4} \ kg \cdot m^2$. Find $N$.

$A$ thin uniform square lamina of side $a$ is placed in the $xy$-plane with its sides parallel to $X$ and $Y$-axes and with its centre coinciding with the origin. Its moment of inertia about an axis passing through a point on the $Y$-axis at a distance $y = 2a$ and parallel to the $X$-axis is equal to its moment of inertia about an axis passing through a point on the $X$-axis at a distance $x = d$ and perpendicular to the $xy$-plane. Then the value of $d$ is:

$A$ square lamina of side $b$ has the same mass as a disc of radius $R$. The moment of inertia of the two objects about an axis perpendicular to the plane and passing through the centre is equal. The ratio $\frac{b}{R}$ is

The moment of inertia of a sphere (mass $M$ and radius $R$) about its diameter is $I$. Four such spheres are arranged as shown in the figure. The moment of inertia of the system about the axis $XX'$ will be (in $,I$)