Consider the following chemical reaction.CH e | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The reaction proceeds in two steps:$1$. $3 CH \equiv CH \xrightarrow{	ext{Red hot Fe tube, } 873 	ext{ K}} C_6H_6$ (Benzene).$2$. $C_6H_6 + CO +

Vedclass · Accepted Answer

$7$

Vedclass · Answer

(D) The reaction proceeds in two steps:$1$. $3 CH \equiv CH \xrightarrow{	ext{Red hot Fe tube, } 873 	ext{ K}} C_6H_6$ (Benzene).$2$. $C_6H_6 + CO + HCl \xrightarrow{AlCl_3} C_6H_5CHO$ (Benzaldehyde) via Gattermann-Koch reaction.In benzaldehyde $(C_6H_5CHO)$,there are $6$ carbon atoms in the benzene ring,all of which are $sp^{2}$ hybridized.The carbonyl carbon atom $(C=O)$ is also $sp^{2}$ hybridized.Therefore,the total number of $sp^{2}$ hybridized carbon atoms is $6 + 1 = 7$.

Consider the following chemical reaction.
$CH \equiv CH \xrightarrow[{(2) CO, HCl, AlCl_3}]{{(1) Red hot Fe tube, 873 K}} \text{Product}$
The number of $sp^{2}$ hybridized carbon atom$(s)$ present in the product is ..........

Similar Questions

Which of the following can decolorize aldehydes and ketones?

Given the reactions:
$CaOCl_2 + H_2O \longrightarrow Ca(OH)_2 + X$
$X + CH_3CHO \longrightarrow Y$
$Y + Ca(OH)_2 \longrightarrow CHCl_3$
What is '$Y$'?

Which among the following is a possible product during cross aldol condensation between propanal (as electrophile) and butanal (as nucleophile)?

Fehling solution reacts with $HCHO$ to form a precipitate of which color?

$CH_3CH=CHCHO$ $\xrightarrow[\text{Aldol condensation}]{OH^{-}}$ $\xrightarrow{\Delta} A$; Product $A$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Consider the following chemical reaction.$CH \equiv CH \xrightarrow[{(2) CO, HCl, AlCl_3}]{{(1) Red hot Fe tube, 873 K}} \text{Product}$The number of $sp^{2}$ hybridized carbon atom$(s)$ present in the product is ..........