Consider the graph given in the following dia | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The instantaneous rate of reaction at a specific time is determined by the slope of the tangent drawn to the concentration-time curve at that poin

Vedclass · Accepted Answer

$\frac{C_4 - C_2}{50 - 30}$

Vedclass · Answer

(D) The instantaneous rate of reaction at a specific time is determined by the slope of the tangent drawn to the concentration-time curve at that point.For the $40^{th}$ second,the tangent passes through points corresponding to $(30, C_2)$ and $(50, C_5)$.The slope of this tangent is calculated as $\frac{\Delta C}{\Delta t} = \frac{C_5 - C_2}{50 - 30}$.Option $(A)$ represents this slope correctly.Options $(B)$ and $(C)$ represent slopes of secant lines that approximate the instantaneous rate at $40 \ s$ by using points on either side of $40 \ s$ (e.g.,$(30, C_2)$ to $(40, C_3)$ or $(20, C_1)$ to $(40, C_3)$).Option $(D)$,$\frac{C_4 - C_2}{50 - 30}$,uses $C_4$ instead of $C_5$,which does not correspond to the tangent line at $40 \ s$. Therefore,it does not represent the instantaneous rate.

Time $(s)$	$0$	$100$	$200$	$300$	$400$	$700$	$800$
$[C_4H_9Cl]$ $(mol \, L^{-1})$	$0.100$	$0.082$	$0.067$	$0.055$	$0.044$	$0.021$	$0.017$

Consider the graph given in the following diagram. Which of the following options does not show the instantaneous rate of reaction at the $40^{th}$ second?

Similar Questions

The rate of a gaseous reaction is given by $r = K[x][y]$. If the volume of the reaction vessel is suddenly reduced to $1/4$ of its initial volume,the rate of the reaction will ............

The average rate of reaction $2SO_{2(g)} + O_{2(g)} \rightarrow 2SO_{3(g)}$ is written as

If the instantaneous rate of reaction is given as $-\frac{1}{a} \frac{d[A]}{dt} = -\frac{1}{b} \frac{d[B]}{dt} = \frac{1}{c} \frac{d[C]}{dt} = \frac{1}{d} \frac{d[D]}{dt}$,then the reaction is represented as:

For the reaction $3A \to 2B$,the rate of reaction is expressed as $\frac{+d[B]}{dt} = \dots$

Vedclass Test Series

Exam Paper Generator

Online Exam Module