Consider the nuclear fission $Ne^{20} \to 2He^4 + C^{12}$. Given that the binding energy per nucleon of $Ne^{20}$,$He^4$,and $C^{12}$ are,respectively,$8.03\, MeV$,$7.07\, MeV$,and $7.86\, MeV$,identify the correct statement.

  • A
    Energy of $12.4\, MeV$ will be supplied.
  • B
    $8.3\, MeV$ energy will be released.
  • C
    Energy of $3.6\, MeV$ will be released.
  • D
    None of these.

Explore More

Similar Questions

The nucleus of $_6C^{12}$ absorbs a neutron and emits a $\beta$-particle. The resulting nucleus is ........

Difficult
View Solution

Suppose we think of the fission of a $^{56}_{26} Fe$ nucleus into two equal fragments,$^{28}_{13} Al$. Is the fission energetically possible? Argue by working out the $Q$-value of the process.
Given: $m(^{56}_{26} Fe) = 55.93494 \; u$ and $m(^{28}_{13} Al) = 27.98191 \; u$.

In a nuclear fusion process,a certain mass of hydrogen is converted into helium,resulting in a mass defect of $0.02866 \, u$. The energy released per $1 \, u$ of mass formed is ......... $MeV$. (Given $1 \, u = 931 \, MeV$)

Difficult
View Solution

The isotope ${}_{5}^{12}B$ having a mass $12.014 \text{ u}$ undergoes $\beta$-decay to ${}_{6}^{12}C$. ${}_{6}^{12}C$ has an excited state of the nucleus $({}_{6}^{12}C^*)$ at $4.041 \text{ MeV}$ above its ground state. If ${}_{5}^{12}B$ decays to ${}_{6}^{12}C^*$, the maximum kinetic energy of the $\beta$-particle in units of $\text{MeV}$ is ($1 \text{ u} = 931.5 \text{ MeV}/c^2$, where $c$ is the speed of light in vacuum).

In nuclear fission,the percentage of mass converted into energy is about: (in $\%$)

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo