In nuclear fission,the percentage of mass converted into energy is about: (in $\%$)

The fission of $_{92}^{235}U$ can be triggered by the absorption of a slow neutron by a nucleus. Similarly,a slow proton can also be used. This statement is

Slowing down of neutrons: In a nuclear reactor,a neutron of high speed (typically $10^{7} \; m s^{-1}$) must be slowed to $10^{3} \; m s^{-1}$ so that it can have a high probability of interacting with isotope $^{235}_{92}U$ and causing it to fission. Show that a neutron can lose most of its kinetic energy in an elastic collision with a light nucleus like deuterium or carbon,which has a mass of only a few times the neutron mass. The material making up the light nuclei,usually heavy water $(D_{2}O)$ or graphite,is called a moderator.

Nuclear fission is best explained by
[$AIPMT$ $2000$]

The binding energy per nucleon for deuteron $(_1H^2)$ and helium $(_2He^4)$ are $1.1 \, MeV$ and $7 \, MeV$ respectively. When two deuterons fuse to form a helium nucleus,the energy released is ........... $MeV$.

Suppose India had a target of producing by $2020\; AD$, $200,000\; MW$ of electric power, ten percent of which was to be obtained from nuclear power plants. Suppose we are given that, on an average, the efficiency of utilization (i.e., conversion to electric energy) of thermal energy produced in a reactor was $25\%$. How much amount of fissionable uranium would our country need per year by $2020$? Take the heat energy per fission of $^{235}_{92}U$ to be about $200\; MeV$.