Convert the given complex number in polar for | vedclass

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(B) Let $z = -1+i$. The polar form is $z = r(\cos 	heta + i \sin 	heta)$.Here,$r \cos 	heta = -1$ and $r \sin 	heta = 1$.Squaring and adding both

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$\sqrt{2}(\cos \frac{3\pi}{4} + i \sin \frac{3\pi}{4})$

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(B) Let $z = -1+i$. The polar form is $z = r(\cos 	heta + i \sin 	heta)$.Here,$r \cos 	heta = -1$ and $r \sin 	heta = 1$.Squaring and adding both equations:$r^2(\cos^2 	heta + \sin^2 	heta) = (-1)^2 + (1)^2$$r^2 = 1 + 1 = 2$$r = \sqrt{2}$ (since $r > 0$).Now,$\cos 	heta = -\frac{1}{\sqrt{2}}$ and $\sin 	heta = \frac{1}{\sqrt{2}}$.Since $\cos 	heta  0$,$	heta$ lies in the $II$ quadrant.The reference angle $\alpha$ is given by $	an \alpha = |\frac{1}{-1}| = 1$,so $\alpha = \frac{\pi}{4}$.In the $II$ quadrant,$	heta = \pi - \alpha = \pi - \frac{\pi}{4} = \frac{3\pi}{4}$.Thus,the polar form is $\sqrt{2}(\cos \frac{3\pi}{4} + i \sin \frac{3\pi}{4})$.

Convert the given complex number in polar form: $-1+i$

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