Copper sulphate dissolves in excess of KCN to | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) When $CuSO_4$ reacts with $KCN$,it first forms a precipitate of cupric cyanide $(Cu(CN)_2)$,which is unstable and decomposes to form cuprous cyani

Vedclass · Accepted Answer

$[Cu(CN)_4]^{3-}$

Vedclass · Answer

(C) When $CuSO_4$ reacts with $KCN$,it first forms a precipitate of cupric cyanide $(Cu(CN)_2)$,which is unstable and decomposes to form cuprous cyanide $(Cu_2(CN)_2)$ and cyanogen gas $((CN)_2)$.$2CuSO_4 + 4KCN \rightarrow 2Cu(CN)_2 + 2K_2SO_4$$2Cu(CN)_2 \rightarrow Cu_2(CN)_2 + (CN)_2$The cuprous cyanide $(Cu_2(CN)_2)$ then dissolves in excess $KCN$ to form the stable soluble complex potassium tetracyanocuprate$(I)$,$K_3[Cu(CN)_4]$.$Cu_2(CN)_2 + 6KCN \rightarrow 2K_3[Cu(CN)_4]$Overall reaction:$2CuSO_4 + 10KCN \rightarrow 2K_3[Cu(CN)_4] + 2K_2SO_4 + (CN)_2$

Copper sulphate dissolves in excess of $KCN$ to give

Similar Questions

Consider the following complexes:
$(a) K_2PtCl_6$
$(b) PtCl_4 \cdot 2NH_3$
$(c) PtCl_4 \cdot 3NH_3$
$(d) PtCl_4 \cdot 5NH_3$
Their electrical conductances in aqueous solutions are:

Some salts,although containing two different metallic elements,give a test for only one of them in solution. Such salts are:

Assign $A$,$B$,$C$,$D$ from the given type of reaction.
$HgI_2 \downarrow + 2KI \longrightarrow K_2[HgI_4]$

Ammonia forms the complex ion $[Cu(NH_3)_4]^{2+}$ with copper ions in alkaline solutions but not in acidic solution. What is the reason for it?

Nitrate is confirmed by the ring test. The brown color of the ring is due to the formation of:

Vedclass Test Series

Exam Paper Generator

Online Exam Module