The correct order of reactivity of CH_3CHO,C_ | vedclass

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(A) The reactivity of carbonyl compounds towards nucleophilic addition depends on two factors: steric hindrance and electronic effects.$1$. Steric hin

Vedclass · Accepted Answer

$CH_3CHO > CH_3COCH_3 > C_2H_5COCH_3$

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(A) The reactivity of carbonyl compounds towards nucleophilic addition depends on two factors: steric hindrance and electronic effects.$1$. Steric hindrance: As the size of the alkyl groups attached to the carbonyl carbon increases,the approach of the nucleophile becomes more difficult.$2$. Electronic effect: Alkyl groups are electron-donating ($+I$ effect),which reduces the electrophilicity of the carbonyl carbon.Comparing the compounds:- $CH_3CHO$ (Acetaldehyde): One alkyl group $(CH_3)$ and one hydrogen atom.- $CH_3COCH_3$ (Acetone): Two methyl groups.- $C_2H_5COCH_3$ (Butan$-2-$one): One methyl group and one ethyl group.Since $CH_3CHO$ has the least steric hindrance and the least electron-donating effect,it is the most reactive.$C_2H_5COCH_3$ has more steric hindrance than $CH_3COCH_3$ due to the larger ethyl group.Therefore,the order of reactivity is $CH_3CHO > CH_3COCH_3 > C_2H_5COCH_3$.

List-$I$ (Reaction)	List-$II$ (Product)
$A$. $\text{Ketone} + NaBH_4$	$I$. $1^\circ$-alcohol
$B$. $\text{Ester} + LiAlH_4$	$II$. $3^\circ$-alcohol
$C$. $RMgX + \text{Ketone}$	$III$. $2^\circ$-alcohol
	$IV$. $\text{Alkane}$

The correct order of reactivity of $CH_3CHO$,$C_2H_5COCH_3$,and $CH_3COCH_3$ towards nucleophilic addition is:

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The major product formed in the following reaction is
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For the given compound,determine the number of hydrogen atoms that are replaced by $D$ upon keeping it for a long time with $\mathop O\limits^\ominus D / D_2O$.

Match the following reactions in List-$I$ with their products in List-$II$.
List-$I$ (Reaction) List-$II$ (Product)
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The reaction of $C_6H_5CH=CHCHO$ with $LiAlH_4$ gives

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