Currents of 10 A and 2 A are passed through | vedclass

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(D) The force per unit length between two parallel current-carrying wires is given by the formula:$F = \frac{\mu_0 I_1 I_2 l}{2 \pi y}$Given:$I_1 = 10

Vedclass · Accepted Answer

$8 	imes 10^{-5} \ N$

Vedclass · Answer

(D) The force per unit length between two parallel current-carrying wires is given by the formula:$F = \frac{\mu_0 I_1 I_2 l}{2 \pi y}$Given:$I_1 = 10 \ A$$I_2 = 2 \ A$$l = 2 \ m$$y = 10 \ cm = 0.1 \ m = 10 	imes 10^{-2} \ m$$\mu_0 = 4 \pi 	imes 10^{-7} \ T \cdot m/A$Substituting the values into the formula:$F = \frac{(4 \pi 	imes 10^{-7}) 	imes 10 	imes 2 	imes 2}{2 \pi 	imes 10 	imes 10^{-2}}$$F = \frac{4 \pi 	imes 10^{-7} 	imes 40}{2 \pi 	imes 0.1}$$F = 2 	imes 10^{-7} 	imes 400$$F = 800 	imes 10^{-7} \ N = 8 	imes 10^{-5} \ N$Therefore,the force acting on conductor $B$ is $8 	imes 10^{-5} \ N$.

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