Daily wages of 110 workers,obtained in a surv | vedclass

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(A) To find the mean daily wages,we use the direct method formula: $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.First,we calculate the class mark $(x_i)$

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$170.18$

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(A) To find the mean daily wages,we use the direct method formula: $\bar{x} = \frac{\sum f_i x_i}{\sum f_i}$.First,we calculate the class mark $(x_i)$ for each interval using the formula: $x_i = \frac{	ext{Lower limit} + 	ext{Upper limit}}{2}$.			Daily wages (in $Rs.$)		Class mark $(x_i)$		Number of workers $(f_i)$		$f_i x_i$				$100-120$		$110$		$10$		$1100$				$120-140$		$130$		$15$		$1950$				$140-160$		$150$		$20$		$3000$				$160-180$		$170$		$22$		$3740$				$180-200$		$190$		$18$		$3420$				$200-220$		$210$		$12$		$2520$				$220-240$		$230$		$13$		$2990$	Sum of frequencies $\sum f_i = 10 + 15 + 20 + 22 + 18 + 12 + 13 = 110$.Sum of products $\sum f_i x_i = 1100 + 1950 + 3000 + 3740 + 3420 + 2520 + 2990 = 18720$.Mean $\bar{x} = \frac{18720}{110} \approx 170.18$.Thus,the mean daily wage is $Rs. 170.18$.

Class	$20-30$	$30-40$	$40-50$	$50-60$	$60-70$	$70-80$	$80-90$
Frequency	$8$	$12$	$27$	$x$	$55$	$37$	$y$

Class	$0-10$	$10-20$	$20-30$	$30-40$	$40-50$	$50-60$
Frequency	$4$	$5$	$9$	$10$	$14$	$8$

Class	$0-20$	$20-40$	$40-60$	$60-80$	$80-100$	$100-120$
Frequency	$8$	$9$	$26$	$23$	$20$	$14$

Class	$21-25$	$26-30$	$31-35$	$36-40$	$41-45$	$46-50$	$51-55$
Frequency	$18$	$32$	$30$	$40$	$25$	$15$	$40$

Daily wages of $110$ workers,obtained in a survey,are tabulated below:

Daily wages (in $Rs.$) Number of workers

$100-120$ $10$

$120-140$ $15$

$140-160$ $20$

$160-180$ $22$

$180-200$ $18$

$200-220$ $12$

$220-240$ $13$

Compute the mean daily wages of these workers (in $Rs.$).

Similar Questions

The mode of the following frequency distribution is $64$ and the total frequency is $200.$ Find the missing frequencies $x$ and $y.$

Class $20-30$ $30-40$ $40-50$ $50-60$ $60-70$ $70-80$ $80-90$

Frequency $8$ $12$ $27$ $x$ $55$ $37$ $y$

For a given frequency distribution,$\bar{x}=20, \Sigma f_{i} u_{i}=-50, n=100$ and $c=10$. Then,assumed mean $A = \ldots \ldots \ldots \ldots$

The median class of the following frequency distribution is ...........
Class $0-10$ $10-20$ $20-30$ $30-40$ $40-50$ $50-60$
Frequency $4$ $5$ $9$ $10$ $14$ $8$

Total frequency $n = 50$.

Find the mode of the following frequency distribution:

Class $0-20$ $20-40$ $40-60$ $60-80$ $80-100$ $100-120$

Frequency $8$ $9$ $26$ $23$ $20$ $14$

Find the mean of the following frequency distribution:

Class $21-25$ $26-30$ $31-35$ $36-40$ $41-45$ $46-50$ $51-55$

Frequency $18$ $32$ $30$ $40$ $25$ $15$ $40$

(in $.675$)

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Daily wages (in $Rs.$)	Number of workers
$100-120$	$10$
$120-140$	$15$
$140-160$	$20$
$160-180$	$22$
$180-200$	$18$
$200-220$	$12$
$220-240$	$13$

Daily wages of $110$ workers,obtained in a survey,are tabulated below: Daily wages (in $Rs.$) Number of workers $100-120$ $10$ $120-140$ $15$ $140-160$ $20$ $160-180$ $22$ $180-200$ $18$ $200-220$ $12$ $220-240$ $13$ Compute the mean daily wages of these workers (in $Rs.$).