For a given frequency distribution,bar{x}=20, | vedclass

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(A) The formula for the mean using the step-deviation method is given by: $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{n} ight) 	imes c$Given va

Vedclass · Accepted Answer

$25$

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(A) The formula for the mean using the step-deviation method is given by: $\bar{x} = A + \left( \frac{\Sigma f_{i} u_{i}}{n} ight) 	imes c$Given values are: $\bar{x} = 20$,$\Sigma f_{i} u_{i} = -50$,$n = 100$,and $c = 10$.Substituting these values into the formula:$20 = A + \left( \frac{-50}{100} ight) 	imes 10$Simplify the expression:$20 = A + (-0.5) 	imes 10$$20 = A - 5$Solving for $A$:$A = 20 + 5$$A = 25$Thus,the assumed mean $A$ is $25$.

Daily wages (in $Rs.$)	Number of workers
$100-120$	$10$
$120-140$	$15$
$140-160$	$20$
$160-180$	$22$
$180-200$	$18$
$200-220$	$12$
$220-240$	$13$

Class	$60-70$	$70-80$	$80-90$	$90-100$	$100-110$	$110-120$
Frequency	$5$	$15$	$20$	$30$	$20$	$8$

For a given frequency distribution,$\bar{x}=20, \Sigma f_{i} u_{i}=-50, n=100$ and $c=10$. Then,assumed mean $A = \ldots \ldots \ldots \ldots$

Similar Questions

For a given frequency distribution,$\Sigma f_{i} u_{i} = -13$,$n = \Sigma f_{i} = 100$,$A = 62.5$ and $c = 15$. Then,mean $\bar{x} = \dots$

Daily wages of $110$ workers,obtained in a survey,are tabulated below:

Daily wages (in $Rs.$) Number of workers

$100-120$ $10$

$120-140$ $15$

$140-160$ $20$

$160-180$ $22$

$180-200$ $18$

$200-220$ $12$

$220-240$ $13$

Compute the mean daily wages of these workers (in $Rs.$).

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