The de-Broglie wavelength of a body of mass m | vedclass

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(D) The de-Broglie wavelength $\lambda$ is related to the momentum $p$ of a particle by the equation $\lambda = \frac{h}{p}$.We know that the kinetic

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$\lambda = \frac{h}{\sqrt{2mE}}$

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(D) The de-Broglie wavelength $\lambda$ is related to the momentum $p$ of a particle by the equation $\lambda = \frac{h}{p}$.We know that the kinetic energy $E$ of a body of mass $m$ is given by $E = \frac{p^2}{2m}$.Rearranging this for momentum,we get $p^2 = 2mE$,which implies $p = \sqrt{2mE}$.Substituting the expression for $p$ into the de-Broglie wavelength formula,we get $\lambda = \frac{h}{\sqrt{2mE}}$.Therefore,the correct option is $D$.

The de-Broglie wavelength of a body of mass $m$ and kinetic energy $E$ is given by:

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